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Hope E.Hope E. 

formula field referencing an URL type custom field failed

Hi All,

I have a custom field which contains the user's linkin URL. 
in my formula I want to use a image instead and linked to my custom field is field if it's filled.

It's not working and will throw an error. if I look at the Url it's like: https://sdworxgroup--int.cs85.my.salesforce.com/www.linkedin.com/in/

so I tried to remove the basic url from it but it still not working.

LEFT($Api.Partner_Server_URL_260, FIND( '/services', $Api.Partner_Server_URL_260)), ''), 

do you have any suggestion? 

thank you

Arvind KumarArvind Kumar
Hi Hope,

I have cross-checked. It is worked on my side.

Please try again, it will work for you.

If you have any issue, you can concern me.

Arvind Kumar
Hope E.Hope E.

Hi Arvind,
when I try this in my dev org, it works perfectly. but in the sandbox not. it'll add the basic url of the org inot the external url.


do you have any idea where it comes from?