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formula field referencing an URL type custom field failed
Hi All,
I have a custom field which contains the user's linkin URL.
in my formula I want to use a image instead and linked to my custom field is field if it's filled.
It's not working and will throw an error. if I look at the Url it's like: https://sdworxgroup--int.cs85.my.salesforce.com/www.linkedin.com/in/
so I tried to remove the basic url from it but it still not working.
IF(ISBLANK(LinkedIn_Profile__c),
(HYPERLINK("http://www.linkedin.com/vsearch/p?type=people&keywords="&FirstName&"+"&LastName&"&sortCriteria=4",
IMAGE("http://www.shebrand.com/wp-content/uploads/2010/07/icon_linkedin1.png","linkedin",15,15))),
HYPERLINK(SUBSTITUTE(LinkedIn_Profile__c,
LEFT($Api.Partner_Server_URL_260, FIND( '/services', $Api.Partner_Server_URL_260)), ''),
IMAGE("http://www.shebrand.com/wp-content/uploads/2010/07/icon_linkedin1.png","linkedin",15,15)))
do you have any suggestion?
thank you
I have cross-checked. It is worked on my side.
Please try again, it will work for you.
If you have any issue, you can concern me.
Thanks,
Arvind Kumar
Hi Arvind,
when I try this in my dev org, it works perfectly. but in the sandbox not. it'll add the basic url of the org inot the external url.
https://xx.csxx.my.salesforce.com/www.linkedin.com/in/xx/
do you have any idea where it comes from?
regards,
Arezou